# MPM2D Sine Law – 2016-01-18

We learned about the Sine Law today.

If you have an acute triangle ABC with corresponding opposite sides a, b, and c, then

$\frac{sin(A)}{a}= \frac{sin(B)}{b}= \frac{sin(C)}{c}$

Or

$\frac{a}{sin(A)}= \frac{b}{sin(B)}= \frac{c}{sin(C)}$

Complete page 402 #1-7 for homework.